Answer:
[tex]tan^{-1}[/tex] ( 24.19 / 10.06 )
Explanation:
starting speed = 20m/s
direction = 41 degrees from due east
after 20 seconds
bus speed = 45m/s
direction = 56 degrees from due east
calculate the angle of the vector that represents the change in the velocity of the bus
change in velocity : ΔV = Vf - Vi
Vf = Vf ( cos βi + sinβj )
= 45m/s ( cos 56 i + sin56 j )
= 25.16 i + 37.31 j
Vi = Vi ( cos ∝ i + sin ∝ j )
= 20 m/s ( cos 41 i + sin 41 i )
= 15.10 i + 13.12j
Hence the change in velocity ΔV ( Vf - Vi )
= 10.06 i + 24.19 j
the angle in degrees ( ∅ ) = [tex]tan^{-1}[/tex] ( 24.19 / 10.06 )
