Answer:
16
Step-by-step explanation:
In order to get the max number of 4-element-subsets of we can select, such that intersection of any 3 of them is empty, we need to calculate the power of the set having four elements. Let the set containing the element be A as shown;
Let set A = {a, b, c, d}
Power of the set P(A) = [tex]2^n[/tex] where:
n is the total number of element in the set. Since we have four elements in the set, n = 4
[tex]P(A) = 2^4\\P(A) = 16[/tex]
This means that the set A have 16 subsets. The subsets of the set are:
{}, {a}, {b}, {c}, {d}, {a, b}, {a, c}, {a, d}, {b, c}, {b, d}, {c, d}, {a, b, c}, {a, b, d}, {b, c, d}. {a, c, d}, {a, b, c, d}.
From all the subsets, it can be seen that intersection of set {a} and {b}, {a} and {c}, {c} and {d} are empty.
Hence the max number of 4-element-subsets of we can select, such that intersection of any 3 of them is empty is 16
