Complete Question
An L-C circuit has an inductance of 0.350 H and a capacitance of 0.290 nF . During the current oscillations, the maximum current in the inductor is 2.00 A .
What is the maximum energy [tex]E_{max}[/tex] stored in the capacitor at any time during the current oscillations?
Express your answer in joules.
Answer:
The value is [tex]E_{max} = 0.7 J [/tex]
Explanation:
From the question we are told that
The inductance is [tex]L = 0.350 \ H[/tex]
The capacitance is [tex]C = 0.290 \ nF = 0.290 *10^{-9 } \ F[/tex]
The current is [tex]I = 2 \ A[/tex]
Generally the maximum energy is mathematically represented as
[tex]E_{max} = \frac{1}{2} * L * I^2[/tex]
=> [tex]E_{max} = \frac{1}{2} * 0.350 * 2^2[/tex]
=> [tex]E_{max} = 0.7 J [/tex]
