The local nursery is waiting for its spring annuals to be delivered, and 20% of the plants ordered are petunias. If the first truck contains 120 plants packed at random, what is the probability that no more than 30 plants are petunias?

Respuesta :

Answer: 0.9147

Step-by-step explanation:

Given: 20% of the plants ordered are petunias.

Let p = 20% = 0.2

Sample size: n = 120

If they follow normal distribution, then mean = np = 120x 0.2 = 24

Standard deviation = [tex]\sqrt{n p(1-p)}=\sqrt{120\times0.2\times.8}[/tex]

[tex]=\sqrt{19.2}\\\\ =4.38[/tex]

The  probability that no more than 30 plants are petunias : [tex]P(\dfrac{X-\mu}{\sigma}\leq \dfrac{30-24}{4.38})[/tex]

[tex]=P(Z<1.37)= 0.9147[/tex]

Hence, the probability that no more than 30 plants are petunias = 0.9147

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