If the pH of a solution increases by 2 units (e.g., from 3 to 5), then the ratio of the new to the original hydronium ion concentration is

This question is incomplete. However, generally hydronium ion (H₃O⁺) is produced when hydrogen ion (usually from an acid) is attracted to the negative pole of water (which is the oxygen part).

To determine the ratio in this case is simple, the ratio of the new to the original hydronium ion concentration is;

the calculate new concentration of hydronium ion, [H₃O⁺]

pH = -log[H₃O⁺] hence,

[H₃O⁺] = log⁻¹pH (meaning antilog of pH)

Kindly note that the pH to be used here is 2 + the original pH given

Hence, if the original pH given is 2

The new [H₃O⁺] will be 4

[H₃O⁺] = log⁻¹ 4

= 10000

Same formula should be used to determine the concentration of the original hydronium ion concentration using the original pH given.

Hence, [H₃O⁺] = log⁻¹ 2

= 100

The ratio of the new to the original hydronium ion concentration will be

10000:100

100:1

adioabiola adioabiola · Answer 2 · 2021-11-30T14:38:21+01:00

The ratio of the new to the original hydronium ion concentration when the pH of a solution increases by 2 is; 1: 100

The Hydroxonium ion is similar to the hydrogen ion concentration and is written as;. {H3O+¹}.

The formula for calculating the pH of a solution is;

pH = -log {H3O+¹}

When the pH increases by 2 units; (e.g., from 3 to 5).

Therefore; By evaluation;

at pH = 3; {H3O+¹} = 10-³

and at pH = 5; {H3O+¹} = 10-⁵.

Therefore; 10-⁵/10-³ = 10-².

In essence; the ratio of the new to the original hydronium ion concentration is; 1 : 100