In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0 represents the worst possible life and 10 represents the best possible life. The responses were normally​ distributed, with a mean of

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Complete Question

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Answer:

a

[tex]P(X < 4) =  0.4141 [/tex]

b

[tex]P(4 < X < 6) =   0.32876[/tex]

c

 [tex]P(X >8) =  0.064037 [/tex]

d

The correct option is  B

Step-by-step explanation:

From the question we are told that

  The mean is  [tex]\mu =  4.5[/tex]

  The standard deviation is [tex]\sigma  =  2.3[/tex]

Generally the  probability that a randomly selected study participant's response was less than 4 is mathematically represented as

       [tex]P(X < 4) =  P(\frac{X - \mu }{\sigma} < \frac{4 - 4.5}{ 2.3}   )[/tex]

[tex]\frac{X -\mu}{\sigma} =  Z (The \  standardized \  value \  of\  X )[/tex]

So

     [tex]P(X < 4) =  P(Z < -0.217  )[/tex]

From the z-table  [tex]P(Z < -0.217  ) =  0.4141[/tex]

So

    [tex]P(X < 4) =  0.4141 [/tex]

Generally the probability that a randomly selected study participant's response was between 4 and 6 is mathematically represented as

     [tex]P(4 < X < 6) =  P( < \frac{4 - 4.5}{ 2.3}  < \frac{X - \mu }{\sigma} < \frac{6 - 4.5}{2.3})[/tex]

=> [tex]P(4 < X < 6) =  P(  \frac{4 - 4.5}{ 2.3}  < \frac{X - \mu }{\sigma} < \frac{6 - 4.5}{2.3})[/tex]

=>   [tex]P(4 < X < 6) =  P(  -0.217  < Z< 0.6522[/tex]

=>   [tex]P(4 < X < 6) =   (Z< 0.6522) -P( Z <  -0.217) [/tex]

From the z-table  

       [tex](Z< 0.6522)  = 0.74286 [/tex]

So  

       [tex]P(4 < X < 6) =  0.74286 -0.4141[/tex]

=>      [tex]P(4 < X < 6) =  0.74286 -0.4141[/tex]

=>      [tex]P(4 < X < 6) =   0.32876[/tex]

Generally the  probability that a randomly selected study participant's response was more than 8 is mathematically represented as

       [tex]P(X > 8) =  P(\frac{X - \mu }{\sigma} > \frac{8 - 4.5}{ 2.3}   )[/tex]

        [tex]P(X > 8) =  P(Z > 1.52174  )[/tex]

From the z-table  [tex]P(Z > 1.52174 ) =  0.064037[/tex]

So

    [tex]P(X >8) =  0.064037 [/tex]

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