We are required to find the price should it charge to maximize its revenue
The price it should charge to maximize its revenue is $38
Equation:
(60 - 2n)(40 + 5n)
open parenthesis
2400 + 300n - 80n - 10n²
2400 + 220n - 10n²
differentiate with respect to n
dR/dn = 220 - 20n
220 - 20n = 0
220 = 20n
divide both sides by n
n = 220/20
n = 11
Revenue maximization price = (60 - 2n)
= 60 - 2(11)
= 60 - 22
= $38
Car rent price = (40 + 5n)
= 40 + 5(11)
= 40 + 55
= $95
Therefore, the price it should charge to maximize its revenue is $38
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