Answer:
The first choice (32m/s) is the closest to the answer
Explanation:
The magnitude of a vector is the distance between the initial and the end point of the vector.
Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:
[tex]\mid \vec{V} \mid =\sqrt{V_x^2+V_y^2}[/tex]
The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.
Calculate the magnitude of the velocity:
[tex]\mid \vec{V} \mid =\sqrt{28^2+15^2}[/tex]
[tex]\mid \vec{V} \mid =\sqrt{784+225}[/tex]
[tex]\mid \vec{V} \mid =\sqrt{1009}[/tex]
[tex]\mid \vec{V} \mid =31.8 \ m/s[/tex]
The first choice (32m/s) is the closest to the answer
