Answer:
The magnitude of the velocity will be 60 m/s.
The distance covered is 3,600 m
Step-by-step explanation:
Constant Acceleration Motion
It's known as a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
If a is the constant acceleration, vo is the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at[/tex]
The distance traveled by the object is calculated as:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]
The bus starts from rest, i.e. vo=0, the acceleration is a=0.5 m/s^2. The magnitude of the velocity at t=2 minutes = 120 seconds is:
[tex]v_f=0+0.5\cdot 120=60 \ m/s[/tex]
The magnitude of the velocity will be 60 m/s.
The distance covered during that time is:
[tex]\displaystyle x=0+\frac{0.5\cdot 120^2}{2}[/tex]
[tex]\displaystyle x=\frac{7,200}{2}[/tex]
x = 3,600 m
The distance covered is 3,600 m
