Answer:
[tex]\huge\boxed{\sf Option \ B}[/tex]
Step-by-step explanation:
In the given triangle:
Opposite to B = 3
Adjacent to B = 6
Hypotenuse = [tex]\sf 3\sqrt{5}[/tex]
We'll use the following trigonometric ratio:
[tex]\sf sin \theta = \frac{opposite }{hypotenuse} \\\\sin \ B = \frac{3}{3\sqrt{5} } \\\\sin \ B = \frac{1}{\sqrt{5} } \\\\Multiplying \ both \ numerator \ and \ denominator \ by \ \sqrt{5} \\\\sin \ B = \frac{\sqrt{5} }{\sqrt{5} * \sqrt{5} } \\\\\boxed{\sf sin \ B = \frac{\sqrt{5} }{5} }[/tex]
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807
