Answer:
y= -5x/2+17/2.... (x is between -5/2)
slope intercept= mx+b
y= -5x/2+17/2
Step-by-step explanation:
The equation of line in slope intercept form which passes through the points (3,1) and (5,-4) is [tex]-\frac{5}{2} x+\frac{17}{2}[/tex] .
The equation of line in the form of [tex]y = mx + b[/tex], is called slope intercept form of a line.
The equation of line from two points is given by
[tex]y -y_{1} = \frac{y_{2} -y_{1} }{x_{2}-x_{1} } (x-x_{1} )[/tex]
According to the given question
We have two points (3,1) and (5, -4)
Therefore, the equation of line which passes through the points (3,1) and (5, -4) is given by
[tex](y -1)=\frac{-4-1}{5-3} (x-3)[/tex]
⇒[tex](y-1)=\frac{-5}{2}(x-3)[/tex]
⇒[tex]y -1=\frac{-5}{2}x+\frac{15}{2}[/tex]
⇒[tex]y =-\frac{5}{2} x+\frac{15}{2} +1[/tex]
⇒[tex]y = -\frac{5}{2}x+\frac{17}{2}[/tex]
Hence, the equation of line in slope intercept form which passes through the points (3,1) and (5,-4) is [tex]-\frac{5}{2} x+\frac{17}{2}[/tex] .
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