Respuesta :

m∠CDF + mEDF = CDE

[tex]x + 25° + 65° = 3x + 10[/tex]

[tex]x + 90° = 3x + 10[/tex]

[tex]90° = 3x + 10 - x[/tex]

[tex]90° = 2x + 10[/tex]

[tex]2x + 10 = 90[/tex]

[tex]2x = 90 - 10[/tex]

[tex]2x = 80[/tex]

[tex]x = \frac{80}{2} [/tex]

[tex]x = 40°[/tex]

mCDE

= 3 × 40 + 10

= 120 + 10

= 130°

Then , m∠CDF =

[tex]x + 25 \\ = 40 + 25 \\ = 65°[/tex]

•°• mCDF = 65°

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