Respuesta :
The reaction yields 177g of Na.
How to calculate the mass of Na?
The balanced equation is
2NaN₃ → 2Na + 3N₂
Either use the mass of NaN₃ or of N₂ to calculate the mass of Na.
Using Mass of NaN₃
By making the following conversions:
mass of NaN₃ → moles of NaN₃ → moles of Na → mass of Na
500 g NaN₃ × [tex]\frac{1 mol NaN_{3} }{65.01 g NaN_{3} }[/tex] = 7.69 mol NaN₃
7.69 mol NaN₃ × [tex]\frac{2 mol Na}{2 mol NaN_{3} }[/tex] = 7.69 mol Na
7.69 mol Na × [tex]\frac{22.99 g Na}{1 mol Na}[/tex] = 176.8 g Na = 177g of Na
Using Mass of N₂
By making the following conversions:
mass of N₂ → moles of N₂ → moles of Na → mass of Na
323.20 g Na ×[tex]\frac{2 mol N_{2} }{28.01 g N_{2} }[/tex] = 11.539 mol N₂
11.539 mol N₂ × [tex]\frac{2 mol Na}{3 mol N_{2} }[/tex] = 7.692 mol Na
7.692 mol Na × [tex]\frac{22.99 g Na}{1 mol Na}[/tex] = 176.85 g Na = 177g of Na
Learn more about how to determine the mass here:-
https://brainly.com/question/24721477
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