A cube of aluminum measures 3 cm on each side and weighs 81 g. What is its density? (HINT: find the volume of the block first)

D=

M=

V=

Respuesta :

Answer:

27

Explanation: volume-3 times 6=18 /mass- 81 times 6= 486....  486 divided by 18 = 27.... a cube has 6 sides.

The density of the aluminum is 3 g/cm³

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance.

[tex]Density = \frac{Mass }{Volume }[/tex]

To obtain the density of the aluminum, we'll begin by calculating the volume of the aluminum. This can be obtained as follow:

From the question given above, each side of the aluminum cube measures 3 cm. Thus,

Length (L) = 3 cm

Width (W) = 3 cm

Height (H) = 3 cm

Volume = Length × Width × Height

Volume = 3 × 3 × 3

Volume = 27 cm³

Therefore, the volume of the aluminum is 27 cm³

Finally, we shall determine the density of the aluminum. This can be obtained as follow:

Mass = 81 g

Volume = 27 cm³

Density =?

[tex]Density = \frac{Mass }{Volume }\\\\Density = \frac{81}{27}[/tex]

Density = 3 g/cm³

Therefore, the density of the aluminum is 3 g/cm³

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