A skater glides off a frozen pond onto a patch of ground at a speed of 1.8 m/s. Here she is slowed at a constant rate of 3.00 m/s. How fast is the skater moving when she has slid 0.37 m across the ground?

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MrRoyal MrRoyal · Answer 1 · 2020-10-25T06:16:21+01:00

Answer:

1.01 m/s

Explanation:

Given

initial speed, u = 1.8m/s

acceleration, a = -3.00m/s² (it's negative because the skater slowed down)

distance, s = 0.37m

Required

Determine the final velocity (v)

This will be solved using the following equation of motion

[tex]v\² = u\² + 2as[/tex]

Substitute values for u, a and s

[tex]v\² = 1.8\² + 2 * -3 * 0.37[/tex]

[tex]v\² = 3.24 - 2.22[/tex]

[tex]v\² = 1.02[/tex]

Take square roots

[tex]v = \sqrt{1.02[/tex]

[tex]v = 1.00995049384[/tex]

[tex]v = 1.01 m/s[/tex] (Approximated)

onyebuchinnaji onyebuchinnaji · Answer 2 · 2021-12-31T13:27:33+01:00

The final speed of the skater when she has slid 0.37 m is 1.0 m/s.

The given parameters:

The final speed of the skater when she has slid 0.37 m is calculated as follows;

[tex]v_f^2 = v_i^2 + 2ad\\\\v_f ^2 = 1.8^2 + 2(3)(-0.37)\\\\v_f^2 = 1.02\\\\v_f = \sqrt{1.02} \\\\v_f = 1.0 \ m/s[/tex]

Thus, the final speed of the skater when she has slid 0.37 m is 1.0 m/s.

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