Answer:
F = 0.483 N
Explanation:
Initial momentum, [tex]P_i= 7\ kg-m/s[/tex]
Final momentum, [tex]P_f= 22\ kg-m/s[/tex]
Time, t = 31 s
We need to find the force of a lead ball. We can use here the impulse momentum theorem.
[tex]\text{Change in momentum}=F\times t[/tex]
F is force
[tex]P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N[/tex]
So, the force is 0.483 N.
