Answer:
Step-by-step explanation:
complex roots always occur in pairs.
roots are 1,2-2i,2+2i
P(x)=a(x-a)(x-b)(x-c)
P(x)=1(x-1)[x-(2-2i)][x-(2+2i)]
=1(x-1)[(x-2)+2i][(x-2)-2i]
=(x-1)[(x-2)²-(2i)²]
=(x-1)[(x-2)²-4i²]
=(x-1)[x²-4x+4-4(-1)]
=(x-1)[x²-4x+4+4]
=(x-1)[x²-4x+8]
=x³-4x²+8x-x²+4x-8
=x³-5x²+12x-8
