Answer:
The acceleration is 2 m/s² in Camila's direction.
Explanation:
The acceleration can be found using the following equation:
[tex] \Sigma F = ma [/tex]
Where
F is the force
m is the mass of the taffy = 1.5 kg
a is the acceleration =?
Since Emma pulls one end of the taffy with 20 N and Camila pulls the other end with 23 N we have:
[tex] F_{C} - F_{E} = ma [/tex]
[tex]23 N - 20 N = 1.5 kg*a [/tex]
[tex] a = 2 m/s^{2} [/tex]
Hence, the acceleration is 2 m/s² in Camila's direction.
I hope it helps you!
