Answer:
a. 16
b. 80
c. Blood type AB
Step-by-step explanation:
Given:
O = 45%
A = 40%
B = 11%
AB = 4%
Total number of donors = 145
a. No. of donors that had type B blood = [tex] \frac{11}{100}*145 = \frac{1,595}{100} = 15.95 [/tex]
Type B blood donors ≈ 16
b. No. of blood donors without blood type O = [tex] \frac{40 + 11 + 4}{100}*145 = \frac{55}{100}*145 = \frac{7,975}{100} = 79.75 [/tex]
Those without blood type O ≈ 80
c. Find the number of people that had type AB:
Type AB = [tex] \frac{4}{100}*145 = 5.8 [/tex] ≈ 6. This is less than 10 donors.
Therefore, blood type AB had less than 10 donors.