Answer:
[tex]\huge\boxed{y+3=-(x+2)}\\or\\\boxed{y-3=-(x+8)}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Put the coordinates of the given point:
(-2, -3); (-8, 3)
[tex]m=\dfrac{3-(-3)}{-8-(-2)}=\dfrac{3+3}{-8+2}=\dfrac{6}{-6}=-1\\\\\text{for}\ (-2;\ -3)\\\\y-(-3)=-1(x-(-2))\\\\y+3=-(x+2)\\\\\text{for}\ (-8;\ 3)\\\\y-3=-1(x-(-8)\\\\y-3=-(x+8)[/tex]
