[tex]\large\underline{\bf \red{Step \:by\: Step \:Explanation:}}[/tex]
Given two equations are :
- 2x = - y + 6.
- -4 x + 3y = 8 .
We may write them as ,
- 2x + y - 6 = 0 .................(i)
- 4x - 3y + 8 = 0 ...............(ii)
Multiplying equⁿ (i) by 2 :
⇒ 2(2x + y - 6 ) = 0.
⇒ 4x + 2y - 12 = 0 .....................(iii) .
Subtract equⁿ (ii) from equⁿ (iii) :-
⇒ 4x + 2y - 12 = 0
ㅤ- 4x + 3y - 8 = 0 [ Sign changes ]
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⇒ 5y - 20 = 0.ㅤㅤㅤㅤㅤ
⇒ 5y = 20.
⇒ y = 20/5.
⇒ y = 4
Put this value in (i) to obtain x .
⇒ 2x + y - 6 = 0.
⇒ 2x +4 - 6 = 0.
⇒ 2x - 2 = 0.
⇒2x = 2 .
⇒ x = 2/2.
⇒ x = 1 .
Hence the value of x is 1 & y is 4.
[tex]\boxed{\purple{\bf\pink{\dag}\:Hence\:the\: correct\: option\:is\:[b]\:(1,4)}}[/tex]
