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John is pushing (horizontally) on a 100 kg bench with a force of 380 Newtons. What is the size of the friction force acting on the bench if the coefficient of static friction is 0.4? Where will the bench be 10 seconds after John starts pushing

Respuesta :

Answer:

392 N, no movement

Explanation:

Im big brain

FaridRjb

Answer:

dx = 0

Explanation:

The Force of Friction = N * coefficient of static friction

N = m * g

=> The Force of Friction = m * g * coefficient of static friction

The Force of Friction = 100 * 10 * 0.4 = 400 (N)

The Force of Friction > The Force of John

=> It won't move!

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