at t=0
x(0) = (-2)* (-6)^3= 432.
nitial position.
At t=2, x(2)=0.
We can see that our particle is moving towards the left on the axis (by getting from 432 to 0
At t>2 and t<6, x(t) <0.
Our particle is still going left - now beyond the y axis
.
At t=6, x(6) = 0
since we were left from the y axis (because we were going negative earlier) that means the particle took a right turn this time.
.
At t>6, x(t)>0 the particle is still going right and will keep on going to infinity.
6 seconds.is answer hope this helps
