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If you had a mixture that was found to contain 1.05g SiO2, 0.69g Cellulose and 1.82g Calcium Carbonate. What percentage calcium carbonate is in the mixture?

Respuesta :

(1.05+0.69+1.82)= 2.56g. %age of calcium carbonate is; (1.82/2.56)*100= 71%
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