Answer:
Width of the sandbox, b = 4.72 feet
Step-by-step explanation:
It is given that,
The area of the sandbox, [tex]A=26\ ft^2[/tex]
Length of the box, [tex]l=5\dfrac{1}{2}\ ft=5.5\ ft[/tex]
We need to find the width of the sandbox. The area of the rectangle is given by :
[tex]A=l\times b[/tex]
b is the width of the sandbox
So, [tex]b=\dfrac{A}{l}[/tex]
[tex]b=\dfrac{26}{5.5}[/tex]
b = 4.72 feet
So, the width of the sandbox is 4.72 feet. Hence, this is the required solution.
