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A train was moving along east at 25 m/s, but brakes for 3 seconds, reducing its velocity to 13 m/s east.
What was its displacement while braking?

Respuesta :

MathPhys

Answer:

57 m

Explanation:

Given:

v₀ = 25 m/s

v = 13 m/s

t = 3 s

FInd: Δx

Δx = ½ (v + v₀) t

Δx = ½ (13 m/s + 25 m/s) (3 s)

Δx = 57 m

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