Answer:
120 gallons of 10% fertilizer and 80 gallons of 20% fertilizer
Step-by-step explanation:
If x is gallons of 10% fertilizer, and y is gallons of 20% fertilizer, then:
x + y = 200
0.10x + 0.20y = 0.14(200)
Solve with substitution:
0.10x + 0.20(200 − x) = 0.14(200)
0.10x + 40 − 0.20x = 28
12 = 0.10x
x = 120
y = 80
