i could really use some help , ive never done this before .:,)

Answer:
Step-by-step explanation: This is what i can do
1. The first graph belongs to this question
[tex]3p+4\geq -14 , 1-5p\geq -39\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:3y+4\ge \:-14:\quad y\ge \:-6\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:1-5y\ge \:-39:\quad y\le \:8\\\\=\begin{bmatrix}y\ge \:-6\\ y\le \:8\end{bmatrix}\\\\\mathrm{1.\:Graph\:each\:inequality\:separately.}\\\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}\\[/tex]
[tex]3.\:The\:solution\:to\:the\:system\:, will\:be\\\:the\:area\:where\:the\:shadings\:from\:each\:\\inequality\:overlap\:one\:another.\\\\\mathrm{See\:graph\:below.}\\\\\begin{bmatrix}y\ge \:-6\\ y\le \:8\end{bmatrix}\quad \mathrm{Unbounded}[/tex]