Explanation:
Given that,
Bill travels 400 m east in 20 seconds and then travels 300 m north in 20 seconds.
(a) Total distance = 400 + 300 = 700 m
(b) Total distance = [tex]\sqrt{400^2+300^2} =500\ m[/tex]
(c) His average speed,
[tex]s=\dfrac{\text{total distance}}{\text{total time}}\\\\s=\dfrac{700\ m}{20\ s}\\\\s=35\ m/s[/tex]
(d) His average velocity,
[tex]v=\dfrac{\text{total displacement}}{\text{total time}}\\\\v=\dfrac{500\ m}{20\ s}\\\\v=25\ m/s[/tex]
Hence, this is the required solution.
