Answer:
v = 5.38 m/s
Explanation:
Given that,
A tennis ball is dropped from 1.48 m above the ground, d = 1.48 m
It rebounds to a height of 0.956 m
We need to find the velocity of the ball when it hits the ground. Using equation of kinematics as follows :
[tex]v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v=\sqrt{2ad+u^2}\\\\v=\sqrt{2\times 9.8\times 1.48+(0)^2}\\\\v=5.38\ m/s[/tex]
So, when the ball hits the ground, its velocity is 5.38 m/s.
