9. The average diameter of an atom is 2 x 10-8 m. What if the average diameter of an atom was 1 cm? How tall would you be?

Respuesta :

Answer:

You'd be [tex]2 * 10^{-6}[/tex] times tall

Step-by-step explanation:

Given

Represent the previous and new diameter by D1 and D2;

[tex]D_1 = 2 * 10^{-8}m[/tex]

[tex]D_2 = 1\ cm[/tex]

To determine how tall you'd be, we need to divide D2 by D1;

[tex]Ratio = \frac{D_2}{D_1}[/tex]

Substitute values for D2 and D1

[tex]Ratio = \frac{2 * 10^{-8}m}{1\ cm}[/tex]

Convert cm to m

[tex]Ratio = \frac{2 * 10^{-8}m}{1 * 0.01\ m}[/tex]

[tex]Ratio = \frac{2 * 10^{-8}m}{0.01\ m}[/tex]

Convert denominator to exponents

[tex]Ratio = \frac{2 * 10^{-8}m}{10^{-2}\ m}[/tex]

[tex]Ratio = \frac{2 * 10^{-8}}{10^{-2}}[/tex]

Apply Law of indices

[tex]Ratio = 2 * 10^{-8} * 10^2[/tex]

[tex]Ratio = 2 * 10^{-8+2}[/tex]

[tex]Ratio = 2 * 10^{-6}[/tex]

Hence;

You'd be [tex]2 * 10^{-6}[/tex] times tall

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