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Calculating Displacement from the Area under a Curve Try Use the graph to answer the question What is the total displacement of the object after 5 seconds? Velocity vs. Time m 70 Velocity (m/s) 60 50 40 30 20 10 0 0 1 2 3 4 5 Time (s) Done Intro 15 of 18​

Calculating Displacement from the Area under a Curve Try Use the graph to answer the question What is the total displacement of the object after 5 seconds Veloc class=

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MathPhys

Answer:

175 m

Explanation:

In a velocity vs time graph, displacement is the area under the curve.

We can calculate this as area of a trapezoid:

A = ½ (10 m/s + 60 m/s) (5 s)

A = 175 m

Or, we can split the area into a rectangle and a triangle.

A = (10 m/s) (5 s) + ½ (60 m/s − 10 m/s) (5 s)

A = 175 m

kiorithompson07

Answer:

175 m

Explanation:

In a velocity vs time graph, displacement is the area under the curve.

We can calculate this as area of a trapezoid:

A = ½ (10 m/s + 60 m/s) (5 s)

A = 175 m

Or, we can split the area into a rectangle and a triangle.

A = (10 m/s) (5 s) + ½ (60 m/s − 10 m/s) (5 s)

A = 175 m

Hope this helps :)

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