A rocket fires its engines to launch straight up from rest with an upward acceleration of 5 m/s2 for 10 seconds. After this time, the engine shuts off and the rocket freely falls straight down back to Earth's surface.

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benmartin benmartin · Answer 1 · 2020-09-19T18:11:47+02:00

Answer:

The graph is the answer to the question.

Explanation:

The rocket launches straight up, and the acceleration is constant.

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okpalawalter8 okpalawalter8 · Answer 2 · 2021-09-04T15:17:51+02:00

The Complete Question is added below

Attached below is the Graph of the off acceleration as a function of time [tex]t=0\ sec[/tex] [tex]t=10sec[/tex]
Attached below is the Graph of the of velocity as a function of time [tex]t=0\ sec[/tex] [tex]t=10sec[/tex]

c) Velocity of the of the rocket after the first 10sec of travel is

[tex]v=50m/s[/tex]

From the Question we are told that

Upward acceleration of 5 m/s^2 for 10 seconds

Rocket freely falls straight down back to Earth's surface

Attached below is the Graph of the off acceleration as a function of time [tex]t=0\ sec[/tex] [tex]t=10sec[/tex]
Attached below is the Graph of the of velocity as a function of time [tex]t=0\ sec[/tex] [tex]t=10sec[/tex]

Generally the Newtons equation for Velocity is mathematically given as

[tex]v=u+at\\\\v=(0)+(5)(10)[/tex]

[tex]v=50m/s[/tex]

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