Point M is between points Land Non N. LN = 6x. LM 4x . , and MN - 27. How would you set up the equation to solve for "×"?Then solve for"×".​

Point M is between points Land Non N LN 6x LM 4x and MN 27 How would you set up the equation to solve for Then solve for class=

Respuesta :

Answer:

[tex] 4x + 8 + 27 = 6x [/tex], [tex] x = 17.5 [/tex]

Step-by-step explanation:

LM = 4x + 8

MN = 27

LN = 6x

Points L, M, and N are collinear, therefore,

[tex] LM + MN = LN [/tex] (segment addition postulate)

Thus, the equation that would be set up to solve for x would be:

[tex] 4x + 8 + 27 = 6x [/tex] (substitution)

Solve for x as follows:

[tex] 4x + 35 = 6x [/tex]

Subtract 4x from both sides

[tex] 4x + 35 - 4x = 6x - 4x [/tex]

[tex] 35 = 2x [/tex]

Divide both sides by 2

[tex] \frac{35}{2} = \frac{2x}{2} [/tex]

[tex] 17.5 = x [/tex]

[tex] x = 17.5 [/tex]

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