Respuesta :
Answer:
y = 2-x
y = 2-(-3)....y = 2 + 3...y = 5
y = 2 - (-2)...y = 2 + 2...y = 4
y = 2 -(-1)...y = 2 + 1...y = 3
y = 2 - 0....y = 2
y = 2 - 1.....y = 1
so using the domain {-3,-2,-1,0,1] the range would be {5,4,3,2,1}
Step-by-step explanation:
The relation between x and y that is given to us is:
y=2-x
Now we are given some domain points i.e. x-values corresponding to that x value we may easily find out the value of y by the help of relation above and plot the corresponding point on the graph.
The domain is: {-3, -2, -1, 0, 1}
when x= -3
we have: y=2-(-3)=2+3=5
i.e. we have point (-3,5)
when x= -2
we have: y=2-(-2)=2+2=4
i.e. the point is: (-2,4)
when x= -1
we have: y=2-(-2)=3
i.e. the point is: (-1,3)
when x=0
we have: y=2-0=2
i.e. the point is: (0,2)
when x= 1
we have: y=2-1=1
i.e. the point that will be plotted is: (1,1)
The function y = 2-x represents a straight line equation. The plot for this function at given values of x is attached below.
How to evaluate a given mathematical expression with variables if values of the variables are known?
You can simply replace those variables with the value you know of them and then operate on those values to get a final value. This is the result of that expression at those values of the considered variables.
How do we make graph of a function?
Suppose the considered function whose graph is to be made is f(x)
The values of 'x' (also called input variable, or independent variable) are usually plotted on horizontal axis, and the output values f(x) are plotted on the vertical axis.
They are together plotted on the point [tex](x,y) = (x, f(x))[/tex]
This is why we usually write the functions as: [tex]y = f(x)[/tex]
The question statement is missing the fact that the function is y = 2 - x
The set of values for which the graph is to be made is {-1, 0, 1, 2, 3}
Putting x = -1, we get:
y = 2 - (-1) = 2+1 = 3
Therefore, a point on the line would be (x, y) = (-1, 3)
- Similarly, for x = 0, y = 2
- for x = 1, y = 1
- for x =2, y = 0
- for x = 3, y = -1
So, points that will be plotted are [tex](-1,3), (0,2), (1, 1), (2,0), (3, -1)[/tex]
Its plot is attached below.
Learn more about evaluating a function at a value here:
https://brainly.com/question/2753269
