Applying a numeric value to the function on the interval, it is found that f is positive on the interval -4 < x < 1.
The function f is given by:
[tex]f(x) = (x + 4)(x - 2)(x - 1)[/tex]
On the interval -4 < x < 1, to find the sign, we find the numeric value for a value of x, which we are going to use x = 0.
Hence:
[tex]f(0) = (0 + 4)(0 - 2)(0 - 1) = 4(-2)(-1) = (-8)(-1) = 8[/tex]
Hence, f is positive on the interval -4 < x < 1.
A similar problem is given at https://brainly.com/question/14556096
Answer:
f is always negative on the interval
Step-by-step explanation:
