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Two objects A and B of mass 52.0 kilograms are placed in a line. Object A hits object B at a velocity of 7.25 meters/second. They undergo elastic collision. What is the total kinetic energy of the system after the collision?

Respuesta :

Explanation:

The collision is elastic, so kinetic energy is conserved.

KE = ½ mv²

KE = ½ (52.0 kg) (7.25 m/s)²

KE ≈ 1370 J

188.5 Joule is the  total kinetic energy of the system after the collision.

What is the kinetic energy of the system after the collision?

Elastic collisions are collisions in which both momentum and kinetic energy are conserved.

The total system kinetic energy before the collision equals the total system kinetic energy after the collision.

If total kinetic energy is not conserved, then the collision is referred to as an inelastic collision.

Mass =52 kg

Velocity  = 7.25

The given formula for kinetic energy is:

K.E. =  [tex]\frac{1}{2} mv^{2}[/tex]

[tex]K.E. = \frac{1}{2} (52 kg *7.25m/s)\\\\K.E. = 188.5 Joule[/tex]

188.5 Joule is the  total kinetic energy of the system after the collision.

Learn more about kinetic energy here:

https://brainly.com/question/12669551

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