Answer:
[tex]Q=23,430J[/tex]
Explanation:
Hello,
In this case, since we compute the required energy via:
[tex]Q=mC\Delta T[/tex]
Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:
[tex]\Delta T=100-20=80\°C[/tex]
Therefore, the energy turns out:
[tex]Q=70g*4.184\frac{J}{g\°C}*80\°C\\ \\Q=23,430J[/tex]
Best regards.
