Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isotope B does this in 43 days. What is the approximate difference in the half-lives of the isotopes?

The answer is 3 days

Respuesta :

The answer is three days

3 days.

Radioactive Isotopes:

  • A radionuclide (also known as a radioactive nuclide, radioisotope, or radioactive isotope) is an unstable nuclide that has an excess of nuclear energy.
  • The extra energy can be released from the nucleus in one of three ways: as gamma radiation; by being transferred to one of its electrons and then released as a conversion electron; or by being created and released from the nucleus as a new particle (alpha particle or beta particle).
  • The radionuclide is considered to experience radioactive decay during such processes.
  • Due to their capability of releasing an electron from an atom, these emissions are categorized as ionizing radiation.

Solution -

[tex]\frac{log0.10}{log0.5} = 3.32[/tex] half-lives.

So, A's half-life is [tex]\frac{33}{3.32} = 9.94[/tex].

B's half-life is [tex]\frac{43}{3.32} = 12.95[/tex].

⇒ 3 days.

Therefore, the correct answer is 3 days.

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