In the adjoining figure,ABC is an isosceles triangle.BO and CO are bisectors of angle ABC and angle ACB respectively. Prove that BOC is an isosceles triangle.

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BOC is an isosceles triangle.

What is the isosceles triangle?

An isosceles triangle is a triangle whose two sides are equal in length.

Here given that ABC is an isosceles triangle in which its two sides AB and AC are equal.

⇒ AB = AC

In a triangle, if two sides are equal then the opposite angles of the triangle are equal in measurement.

⇒m∠ABC = m∠ACB

As.BO and CO are the angle bisectors of angle ∠ABC and angle ∠ACB respectively.

As BO is the angle bisector of the angle ∠ABC

⇒ ∠ABO= ∠OBC= (1/2)∠ABC

As CO is the angle bisector of the angle ∠ACB

⇒ ∠ACO= ∠OCA= (1/2)∠ACB

From the above it is clear that

m∠ABC = m∠ACB

dividing 1/2 on both sides

⇒(1/2)m∠ABC = (1/2)m∠ACB

⇒∠OBC= ∠OCA

In a triangle, if two angles are the same then their opposite sides are also the same in length.

⇒ OC=OB

⇒ As two sides of the triangle are equal then triangle ΔBOC is an isosceles triangle.

Therefore triangle ΔBOC is an isosceles triangle.

Learn more about the isosceles triangle

here: https://brainly.com/question/1475130

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