The final velocity of it travels a distance of 0.5 m while accelerating is v = 300 m/s.
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⠀⠀⠀⠀Let's solve the question by using the equations of motion. It is given by,
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[tex]\star \: { \boxed{ \sf{ \purple{{v}^{2} = {u}^{2} + 2as}}}}[/tex]
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[tex] \: \: \: \: \: \: \: \: \: \: \: { \underline{ \sf{Substituting \: the \: values, }}}[/tex]
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[tex]: \implies \sf \: \: \: {{v}^{2} = {u}^{2} + 2as} \\ \\ \\ [/tex]
[tex]: \implies \sf \: \: \: {v}^{2} = ( {0)}^{2} + 2(0.5)(90 000) \\ \\ \\ [/tex]
[tex]: \implies \sf \: \: \: {v}^{2} = 90 000 \\ \\ \\ [/tex]
[tex]: \implies \sf \: \: \:{ \boxed{ \bf{ \red{ v= 300 m/s }}}} \: \bigstar \\ \\ [/tex]
Therefore, The final velocity of it travels a distance of 0.5 m while accelerating is v = 300 m/s .
~TheInsaneGirl
