Answer:
The helicopter must cover a straight line distance of approximately 61.270 miles from the hospital to the wreck site.
Step-by-step explanation:
Let suppose that Air Care helicopter travels in straight line from the hospital to the wreck site, we can determine that distance ([tex]d[/tex]), measured in miles, by using the following Pythagorean identity from Analytical Geometry:
[tex]d = \sqrt{(x_{W}-x_{H})^{2}+(y_{W}-y_{H})^{2}}[/tex]
Where:
[tex]x_{W}[/tex], [tex]y_{W}[/tex] - Location of the wreck site, measured in miles.
[tex]x_{H}[/tex], [tex]y_{H}[/tex] - Location of the hospital, measured in miles.
If the location of the wreck site and the hospital are [tex](13, -14)[/tex] and [tex](-42, 7)[/tex], respectively. The distance that helicopter must cover is:
[tex]d = \sqrt{[13-(-42)]^{2}+[(-14)-13]^{2}}[/tex]
[tex]d \approx 61.270\,mi[/tex]
The helicopter must cover a straight line distance of approximately 61.270 miles from the hospital to the wreck site.
