Answer:
Follows are the solution to this question:
Explanation:
The question 1, answer can be defined as follows:
Every three is mowing lawns for their entirety.(A):
[tex]\to 1 \times 10 + 1\times 10 + 2 \times 10 \\\\\to 10 +10 +20 \\\\\to 40[/tex]
Both three have to wash cars both their time.
Each of them spends half the time on any task. (B):
[tex]\to 1 \times 10 + 2 \times 10 + 1 \times 10 \\\\\to 10 +20 +10 \\\\\to 40[/tex]
(C):-
For mowing:
[tex]\to 1 \times 5 + 1 \times 5 + 2 \times 5 \\\\\to 5 + 5 + 10\\\\\to 20[/tex]
For Cars:
[tex]\to 1 \times 5 + 2 \times 5 + 1 \times 5 \\\\\to 5 + 10 + 5\\\\\to 20[/tex]
Half time spent on every operation, Gilberto washes only cars and Lorenzo mows just lawns. (D):
For mowing:
[tex]\to 1 \times 5 +2 \times 10 \\\\\to 5+20 \\\\\to 25[/tex]
For Cars:
[tex]\to 1 \times 5 +2 \times 10\\\\\to 5 +20\\\\\to 25[/tex]
In question 2, the answer is true because Its output options only at maximum have a kinked form since each employee is continuously engaged in coping with both the mowing lawns as well as washing cars. Charles, for both tasks, becomes equally productive. Gilberto is efficient in the cleaning of cars half and also in the mowing of ponds although Lorenzo has greater productivity.