Answer:
The value is [tex] z = 15.7 mg[/tex]
Explanation:
From the question we are told that
The mass of 9-fluorenone is m = 19 mg
The volume of diethyl ether V = 5 ml
The volume of water is [tex]V_w = 10 ml[/tex]
The equilibrium constant for 9-fluorenone is [tex]K_p = 9.5[/tex]
Generally the equilibrium constant for 9-fluorenone is mathematically represented as
[tex]K_p = \frac{ \frac{z }{V} }{ \frac{m - x }{V_w} }[/tex]
Here z is the remaining mass of 9-fluorenone
=> [tex]9.5 = \frac{ \frac{z }{5} }{ \frac{19 - z }{ 10} }[/tex]
=> [tex]9.5 = \frac{2z}{19 - z}[/tex]
=> [tex] z = 15.7 mg[/tex]
