Answer :
The position vector is [tex]d\hat{i}-h\hat{j}[/tex]
Explanation :
Given that,
Height = h
Distance = d
Suppose, A student throws a water balloon with speed v₀ from a height h = 1.98 mat an angle θ = 21° above the horizontal toward a target on the pound. The target is located a horizontal distance d = 65 in from the student's feet. Assume that the balloon moves without air resistance. Use a Cartesian coordinate system with the origin at the balloon's initial position
We know that,
The initially position vector is
[tex]s_{i}=0\hat{i}+h\hat{j}[/tex]
The final position vector is
[tex]s_{f}=d\hat{i}+0\hat{j}[/tex]
We need to calculate the position vector
Using formula of position vector
[tex]r=s_{f}-s_{i}[/tex]
Put the value into the formula
[tex]r=d\hat{i}+0\hat{j}-0\hat{i}-h\hat{j}[/tex]
[tex]r=d\hat{i}-h\hat{j}[/tex]
Hence, The position vector is [tex]d\hat{i}-h\hat{j}[/tex]
