Determine the molecular geometry based on the description of bonding and lone pairs of electrons around the central atom. Three double bonds and no lone pairs of electrons Choose... Two single bonds and two lone pairs of electrons Choose... Five single bonds and no lone pairs of electrons Choose... Three single bonds and one lone pair of electrons Choose... Two double bonds and no lone pairs of electrons Choose... Four single bonds and no lone pairs of electrons Choose... Six single bonds and no lone pairs of electrons Choose...

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Answer:

Three double bonds and no lone pairs of electrons- trigonal planar

Two single bonds and two lone pairs of electrons-bent

Five single bonds and no lone pairs of electrons- trigonal bipyramidal

Three single bonds and one lone pair of electrons- trigonal pyramidal

Two double bonds and no lone pairs of electrons - linear

Four single bonds and no lone pairs of electrons- tetrahedral

Six single bonds and no lone pairs of electrons- octahedral

Explanation:

The valence shell electron pair repulsion theory gives a description of the shape of a molecule based on the number of regions of electron density present on the valence shell of the central atom of the molecule.

The molecules are distorted away from the shape predicted on the basis of the VSEPR by the presence of lone pairs on the valence shell of the central atom in the molecule. In the absence of lone pairs, the shape of a molecule is exactly the shape predicted on the basis of the VSEPR theory.

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