Answer:
d = 303.33 m
Explanation:
Given that,
Acceleration of Doc Brown is 2.52 m/s²
The initial speed of Doc Brown is 0 as it was at rest.
Final speed of Doc Brown is 39.1 m/s
We need to find the distance between he and Marty. Let the distance is d. Using equation of motion as follows :
[tex]v^2-u^2=2ad\\\\\text{Put u = 0}\\\\d=\dfrac{v^2}{2a}\\\\d=\dfrac{(39.1)^2}{2\times 2.52}\\\\d=303.33\ m[/tex]
So, the distance between he and Marty is 303.33 m.
