[tex]\mathbf{Task. ~}\mathrm{Is} ~ \sqrt{36} ~ \mathrm{rational~or~irrational.~ Why?}[/tex]
[tex]\mathbf{Rational~numbers~}\mathrm{are~numbers~that~can~be~represented~as~ordinary~ fractions.}[/tex]
[tex]\mathrm{Examples \colon} ~ \dfrac{1}{2}; \ 0{,}5; \ -1\dfrac{2}{3} ; \ 0{,}(3).[/tex]
[tex]\mathrm{All~integers~are~rational~numbers \colon} ~ 0; ~ 6; ~ 121; ~ 1 \ 000 \ 000; ~ {-5}; ~ {-41}[/tex]
[tex]\mathbf{Irrational~numbers~}\mathrm{are~numbers~that~are~not~rational.}[/tex]
[tex]\mathrm{Examples \colon} ~ \pi, ~ e, ~ \sqrt{3}, ~ \sqrt[3]{7}, ~ \log_{3}2[/tex]
[tex]\mathrm{Since} ~ \sqrt{36} = 6 ~ \mathrm{then~it~is~a~rational~number.}[/tex]
[tex]Answer \colon ~ \mathrm{rational~number}. ~ \blacktriangle[/tex]
