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Write an equation for the nth term of the arithmetic sequence. Then find a50. −29, −12, 5, 22, . . . an = a50 =

Respuesta :

Answer:

             [tex]\bold{a_n=17n+46}\\\\\bold{a_{50}=896}[/tex]

Step-by-step explanation:

−29, −12, 5, 22,  ...

-12-(-29) = 17;   5-(-12) = 17;   22-5 = 17  ⇒ d = 17

first term:  a = -29

difference:  d = 17

so the formula:

                         [tex]a_n=a+d(n-1)\\\\a_n=-29+17(n-1)\\\\a_n =-29+17n-17\\\\\underline{a_n=17n+46}[/tex]                        

and:

   [tex]a_{50}=17\cdot50+46=850+46 = 896[/tex]

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