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A driver drops the top of a 6.9 m tall platform. What is the drivers velocity as she hits the water below

Respuesta :

MathPhys

Answer:

11.6 m/s

Explanation:

Given:

Δy = 6.9 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (6.9 m)

v = 11.6 m/s

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